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Chemistry · Class 12 · Chapter 10

Biomolecules

Carbohydrates, proteins, vitamins and nucleic acids are organic compounds, and this chapter looks at them through the eyes of a chemist: functional groups, ring structures and the bonds that link small units into large ones. The questions are mostly factual, so a careful reading of this page together with NCERT pays off quickly.

In this chapter: classification of carbohydrates, preparation and structure of glucose (open chain and cyclic), anomers and Haworth structures, fructose, disaccharides and polysaccharides, amino acids and the peptide bond, levels of protein structure, denaturation, enzymes, vitamins, nucleic acids, and a short note on hormones.

Carbohydrates

Carbohydrates are optically active polyhydroxy aldehydes or ketones, or compounds that give these on hydrolysis. Many fit the formula Cx(H2O)y, but the formula alone is not a definition: rhamnose (C6H12O5) is a carbohydrate that does not fit it, and acetic acid (C2H4O2) fits it but is not a carbohydrate.

  • Monosaccharides cannot be hydrolysed further: glucose, fructose, ribose. They are aldoses (with -CHO) or ketoses (with C=O), and trioses to heptoses by carbon count. Glucose is an aldohexose; fructose is a ketohexose.
  • Oligosaccharides give 2 to 10 monosaccharide units on hydrolysis. Disaccharides such as sucrose, maltose and lactose give two.
  • Polysaccharides give a large number of units: starch, cellulose, glycogen.
  • Reducing sugars reduce Fehling's solution and Tollens' reagent. All monosaccharides are reducing; among disaccharides, maltose and lactose are reducing but sucrose is non-reducing.

Glucose

Preparation: sucrose boiled with dilute HCl or H2SO4 in alcoholic solution gives glucose and fructose in equal amounts. Commercially, starch is hydrolysed by boiling with dilute H2SO4 at 393 K under pressure.

Reaction of glucoseProductWhat it shows
Prolonged heating with HIn-HexaneSix carbons in a straight chain
Hydroxylamine; HCNOxime; cyanohydrinA carbonyl group is present
Bromine water (mild oxidant)Gluconic acid (six carbons)The carbonyl is an aldehyde group
Acetic anhydrideGlucose pentaacetateFive -OH groups on different carbons
Nitric acidSaccharic acid (a dicarboxylic acid)A primary alcohol (-CH2OH) group is present

Natural glucose is D-(+)-glucose. "D" describes the configuration: in the Fischer projection, the -OH on the lowest chiral carbon (C-5) is on the right, as in D-(+)-glyceraldehyde. "(+)" means it is dextrorotatory. The two symbols are independent of each other.

Cyclic structure

The open-chain formula could not explain several facts: glucose does not give Schiff's test and does not form the NaHSO3 addition product; glucose pentaacetate does not react with hydroxylamine, so no free -CHO is present; and glucose exists in two crystalline forms, α (m.p. 419 K) and β (m.p. 423 K). The explanation is that the -OH on C-5 adds to the -CHO group to form a six-membered cyclic hemiacetal.

Ring closure makes C-1 a new chiral centre, so two forms arise, differing only in the configuration at C-1. They are called anomers, and C-1 is the anomeric carbon. The six-membered ring (five C and one O) resembles pyran, so the forms are named α-D-glucopyranose and β-D-glucopyranose.

Haworth structures of the two anomers of D-glucopyranosewww.iitmedicoguide.comOCH₂OHHOHOHOHHO12345OCH₂OHOHHOHOHHO12345α-D-GlucopyranoseC-1 OH down (opposite to CH₂OH)β-D-GlucopyranoseC-1 OH up (same side as CH₂OH)www.iitmedicoguide.com
The thick edge of each ring faces the reader. The two anomers differ only at C-1, the anomeric carbon; ring hydrogens on C-2 to C-5 are left out for clarity.

Fructose

Fructose, C6H12O6, is a ketohexose with the keto group at C-2. Natural fructose is D-(−)-fructose (laevorotatory). It forms a five-membered ring by addition of the C-5 -OH to the C-2 carbonyl; the ring resembles furan, so the forms are called α- and β-D-fructofuranose.

Disaccharides and polysaccharides

Two monosaccharide units are joined by a glycosidic linkage through an oxygen atom, with loss of a water molecule.

SugarUnits and linkageKey points
Sucroseα-D-glucose (C-1) and β-D-fructose (C-2)Both reducing groups are used in the link, so it is non-reducing. Sucrose is dextrorotatory; its hydrolysis gives dextrorotatory glucose and more strongly laevorotatory fructose, so the rotation changes sign. The product mixture is called invert sugar
MaltoseTwo α-D-glucose units, C-1 of one to C-4 of the otherFree aldehyde can form at C-1 of the second unit, so it is reducing
Lactose (milk sugar)β-D-galactose (C-1) and β-D-glucose (C-4)Reducing
StarchAmylose (15 to 20%): water soluble, unbranched chain of α-D-glucose units joined C-1 to C-4. Amylopectin (80 to 85%): insoluble, branched; C-1 to C-4 chains with C-1 to C-6 branch pointsMain storage polysaccharide of plants
CelluloseStraight chains of β-D-glucose units joined C-1 to C-4Main constituent of plant cell walls; humans cannot digest it
GlycogenLike amylopectin but more highly branched"Animal starch", stored in liver, muscles and brain; also found in yeast and fungi

Proteins

Amino acids

Proteins are built from α-amino acids, which have an amino group and a carboxyl group on the same carbon: RCH(NH2)COOH. About twenty of them occur in proteins. Amino acids that the body can make are non-essential; those that must come from the diet are essential (for example valine, leucine, isoleucine, lysine, threonine, methionine, phenylalanine and tryptophan).

  • They are classed as neutral, acidic or basic depending on the relative number of amino and carboxyl groups.
  • In aqueous solution the -COOH loses a proton and the -NH2 gains one, giving a dipolar ion, the zwitterion (H3N+-CHR-COO−). Amino acids are therefore amphoteric, and they are colourless crystalline solids with high melting points, behaving more like salts than like typical amines or acids.
  • Except glycine (R = H), all naturally occurring α-amino acids are optically active, and most have the L configuration.

Peptide bond

The -COOH of one amino acid and the -NH2 of another combine with loss of water to form an amide link, -CO-NH-, called the peptide bond.

Peptide bond formation between glycine and alaninewww.iitmedicoguide.comH₂NCH₂COOHglycine (Gly)+HNHCHCH₃COOHalanine (Ala)− H₂OH₂NCH₂CONHCHCH₃COOHpeptide bond (-CO-NH-)Glycylalanine(Gly-Ala), a dipeptidewww.iitmedicoguide.com
The OH from the carboxyl group of glycine and an H from the amino group of alanine leave as water. The new C-N bond, shown in amber, is the peptide bond; the chain still has a free -NH₂ at one end and a free -COOH at the other.

Two amino acids give a dipeptide, three a tripeptide, and so on; more than ten give a polypeptide. A polypeptide with more than a hundred amino acid residues and molecular mass above 10,000 u is called a protein.

Worked example: How many different tripeptides can be made from glycine (Gly), alanine (Ala) and phenylalanine (Phe) if each is used exactly once? How many peptide bonds does each contain?
Solution: the three residues can be arranged in 3 × 2 × 1 = 6 sequences: Gly-Ala-Phe, Gly-Phe-Ala, Ala-Gly-Phe, Ala-Phe-Gly, Phe-Gly-Ala and Phe-Ala-Gly. They are all different, because each chain has a definite N-terminal and C-terminal end. A tripeptide has 3 − 1 = 2 peptide bonds.

Structure of proteins

  • Fibrous proteins have parallel polypeptide chains held by hydrogen and disulphide bonds; they are generally insoluble in water (keratin in hair, wool and silk; myosin in muscle). Globular proteins have chains coiled into spherical shapes and are usually water soluble (insulin, albumins).
  • Primary structure: the sequence of amino acids. Any change in the sequence gives a different protein.
  • Secondary structure: the shape of the chain. In the α-helix, the chain forms a right-handed coil with each -NH group hydrogen bonded to a C=O group of an adjacent turn. In the β-pleated sheet, chains lie side by side, almost fully stretched, and are held by hydrogen bonds between chains.
  • Tertiary structure: further folding of the chain, giving the overall fibrous or globular shape. It is held by hydrogen bonds, disulphide links, van der Waals forces and electrostatic attractions.
  • Quaternary structure: the arrangement of two or more polypeptide subunits relative to each other, as in haemoglobin.

Denaturation: a change in temperature or pH disturbs the hydrogen bonds, so the globules unfold and helices uncoil. Secondary and tertiary structures are lost and the protein loses its biological activity, but the primary structure is unchanged. Examples: coagulation of egg white on boiling and curdling of milk by lactic acid produced by bacteria.

Enzymes

Enzymes are biological catalysts, and almost all of them are globular proteins. Each is highly specific for a particular reaction and substrate. They are usually named after the substrate or reaction with the ending -ase: maltase converts maltose into glucose; oxidoreductases catalyse oxidation of one substrate with reduction of another. Like other catalysts, enzymes work by lowering the activation energy of the reaction.

Vitamins

Vitamins are organic compounds needed in small amounts in the diet for normal growth and health. Fat soluble vitamins (A, D, E, K) are stored in the liver and adipose tissue. Water soluble vitamins (B group and C) must be supplied regularly, since they are readily excreted in urine and cannot be stored, vitamin B12 being the exception.

VitaminDeficiency disease
AXerophthalmia (hardening of the cornea), night blindness
B1 (thiamine)Beri beri (loss of appetite, retarded growth)
B2 (riboflavin)Cheilosis (fissuring at the corners of the mouth and lips), digestive disorders, burning sensation of the skin
B6 (pyridoxine)Convulsions
B12Pernicious anaemia
C (ascorbic acid)Scurvy (bleeding gums)
DRickets in children, osteomalacia in adults
EIncreased fragility of red blood cells and muscular weakness
KIncreased blood clotting time

Nucleic acids

Nucleic acids, DNA (deoxyribonucleic acid) and RNA (ribonucleic acid), are long polymers of nucleotides. A nucleotide has three parts: a nitrogenous base, a pentose sugar and a phosphate group. Base plus sugar alone is a nucleoside.

 DNARNA
Sugarβ-D-2-deoxyriboseβ-D-ribose
BasesAdenine, guanine, cytosine, thymineAdenine, guanine, cytosine, uracil
StructureDouble helix of two complementary strandsSingle strand
RoleChemical basis of heredity; replicates itselfProtein synthesis: messenger (m-RNA), ribosomal (r-RNA) and transfer (t-RNA)

Nucleotides are joined by phosphodiester linkages between the 5′ and 3′ carbons of neighbouring sugars. In the double helix, the two strands are held by hydrogen bonds between specific base pairs: adenine pairs with thymine (two hydrogen bonds) and guanine with cytosine (three hydrogen bonds).

Hormones (general idea)

Hormones are chemical messengers made by endocrine glands and carried by the blood to target tissues. Some are steroids (oestrogens and androgens), some are polypeptides (insulin, endorphins) and some are amino acid derivatives (adrenaline, noradrenaline, thyroxine). Insulin and glucagon together keep blood glucose within a narrow range.

Common mistakes: (1) Reading "D" as dextrorotatory. D is configuration; (+) is rotation, and D-fructose is laevorotatory. (2) Calling sucrose a reducing sugar. (3) Mixing up the linkages: amylose and maltose are α(1→4), cellulose is β(1→4), and amylopectin and glycogen also have α(1→6) branches. (4) Saying denaturation breaks peptide bonds; the primary structure survives. (5) Putting thymine in RNA or uracil in DNA.

JEE and NEET focus

  • Classification of carbohydrates and which sugars are reducing.
  • Reactions that establish the open-chain structure of glucose, and the facts that need the cyclic structure; anomers and Haworth forms.
  • Composition and linkages of sucrose, maltose, lactose, starch, cellulose and glycogen; invert sugar.
  • Zwitterions, essential amino acids, the peptide bond, levels of protein structure and denaturation.
  • Vitamin deficiency diseases; DNA vs RNA sugars and bases, base pairing and phosphodiester links.

Practice questions

On prolonged heating with HI, glucose gives:

  1. Gluconic acid
  2. n-Hexane
  3. Saccharic acid
  4. Sorbitol
Show answer
B. This shows that the six carbons are in a straight chain.

Sucrose is a non-reducing sugar because:

  1. It is a disaccharide
  2. It contains fructose
  3. The glycosidic link joins C-1 of glucose and C-2 of fructose, using both reducing groups
  4. It is dextrorotatory
Show answer
C. No free aldehyde or ketone group can form.

α-D-glucose and β-D-glucose differ in the configuration at:

  1. C-1
  2. C-2
  3. C-4
  4. C-5
Show answer
A. They are anomers; C-1 is the anomeric carbon.

Cellulose is a polymer of:

  1. α-D-glucose
  2. β-D-glucose
  3. β-D-fructose
  4. α-D-galactose
Show answer
B. Units are joined by β(1→4) glycosidic links.

The branch points in amylopectin are formed by:

  1. C-1 to C-4 α-glycosidic links
  2. C-1 to C-6 α-glycosidic links
  3. C-1 to C-4 β-glycosidic links
  4. Peptide links
Show answer
B. The main chains are C-1 to C-4; branches arise through C-1 to C-6 links.

Which base is present in RNA but not in DNA?

  1. Adenine
  2. Thymine
  3. Uracil
  4. Cytosine
Show answer
C. DNA has thymine in its place.

Pernicious anaemia is caused by deficiency of:

  1. Vitamin B1
  2. Vitamin B6
  3. Vitamin B12
  4. Vitamin C
Show answer
C. B1 deficiency causes beri beri, B6 convulsions and C scurvy.

During denaturation of a protein, which structure remains intact?

  1. Primary
  2. Secondary
  3. Tertiary
  4. Quaternary
Show answer
A. Peptide bonds are not broken; only the folding is lost.
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