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Chemistry · Class 12 · Chapter 4

The d- and f-Block Elements

Transition metals are the metals of everyday life: iron, copper, chromium, nickel. Most of their special behaviour, from coloured ions to magnetism to catalysis, follows from partly filled d orbitals. If you can write the electronic configuration of an ion correctly, half of this chapter is already done.

In this chapter: position and electronic configuration of d-block elements, trends in size, ionisation enthalpy and oxidation states, electrode potentials, magnetic moment, coloured ions, complex formation, catalytic behaviour, interstitial compounds and alloys, potassium dichromate and potassium permanganate, lanthanoids and lanthanoid contraction, actinoids.

Position and electronic configuration

The d-block occupies groups 3 to 12 of the periodic table. There are four transition series: 3d (Sc to Zn), 4d (Y to Cd), 5d (La, Hf to Hg) and 6d (Ac, Rf to Cn). The f-block, placed separately at the bottom, has the lanthanoids (Ce to Lu, filling 4f) and the actinoids (Th to Lr, filling 5f).

A transition element is one that has an incompletely filled d subshell in its ground state or in any of its common oxidation states. Zinc, cadmium and mercury have a full d10 configuration in the ground state and in their common oxidation states, so they are not regarded as transition metals, although they are studied with them. Copper (3d104s1) counts as a transition metal because Cu2+ is 3d9.

General configuration: (n−1)d1−10ns1−2. Palladium (4d105s0) is an exception. In the 3d series, Cr is 3d54s1 and Cu is 3d104s1, because half-filled and completely filled d subshells are extra stable. When a transition metal forms an ion, the 4s electrons are removed first: Fe is [Ar]3d64s2, Fe2+ is [Ar]3d6 and Fe3+ is [Ar]3d5.

General properties of transition elements

Physical properties and enthalpy of atomisation

Almost all transition elements are hard, lustrous metals with high melting and boiling points, typical metallic structures and good thermal and electrical conductivity. Zn, Cd and Hg are exceptions with low melting points (Hg is a liquid). The strong metallic bonding comes from the participation of (n−1)d as well as ns electrons, which also gives high enthalpies of atomisation. These peak near the middle of each series, where the number of unpaired d electrons is largest. Metals of the 4d and 5d series have higher enthalpies of atomisation than the 3d metals, so heavy transition metals more often form metal-metal bonds.

Atomic and ionic sizes

Across a series, ions of the same charge become smaller as nuclear charge increases, because a new d electron shields the others poorly. The decrease is small in the middle of the 3d series. The 5d elements are almost the same size as the 4d elements (Zr 160 pm, Hf 159 pm) because of the lanthanoid contraction: the 4f subshell fills before the 5d series begins, and f electrons shield the nucleus very poorly.

Ionisation enthalpy

Ionisation enthalpy increases along each series, but less steeply than for main group elements, and not smoothly. Irregularities come from the extra stability of d5 and d10 configurations. For example, the third ionisation enthalpy of Mn is very high because Mn2+ (d5) resists losing an electron, while the second ionisation enthalpies of Cr and Cu are high because removing an electron from Cr+ (d5) or Cu+ (d10) breaks a stable configuration.

Oxidation states

ElementScTiVCrMnFeCoNiCuZn
Common states+3+2, +3, +4+2 to +5+2, +3, +6 (also +4, +5)+2 to +7+2, +3 (also +4, +6)+2, +3 (also +4)+2 (also +3, +4)+1, +2+2
  • Variable oxidation states arise because (n−1)d and ns electrons have similar energies. The largest number of states is shown in the middle of the series; Mn shows every state from +2 to +7.
  • Early members (Sc, Ti) show fewer states because they have few electrons to lose; late members (Cu, Zn) because they have too many d electrons and few vacant orbitals to use.
  • In the p-block the lower oxidation state becomes more stable down a group (inert pair effect). In the d-block the opposite is true: Mo(VI) and W(VI) are more stable than Cr(VI).
  • Fluorine and oxygen stabilise the highest oxidation states. The highest fluoride of Mn is MnF4, but its highest oxide is Mn2O7, because oxygen can form multiple bonds to the metal.

Standard electrode potentials

The E°(M2+/M) values of the 3d metals are mostly negative and become less negative across the series. Copper is the only 3d metal with a positive E°(M2+/M) (+0.34 V), so it does not liberate H2 from dilute acids. Its high enthalpy of atomisation plus ionisation enthalpies is not balanced by the hydration enthalpy of Cu2+.

Among E°(M3+/M2+) values, Mn3+/Mn2+ is high (+1.57 V) because Mn2+ is a stable d5 ion, while Fe3+/Fe2+ is comparatively low (+0.77 V) because Fe3+ is d5. Cr2+ is a strong reducing agent since it readily becomes Cr3+, whose t2g3 configuration (in water) is especially stable; Mn3+ and Co3+ are strong oxidising agents in solution.

Magnetic properties

Substances with unpaired electrons are paramagnetic (attracted by a magnetic field); those with all electrons paired are diamagnetic. For 3d ions, the magnetic moment can be estimated from the number of unpaired electrons n using the spin-only formula:

μ = √n(n + 2) BMBM = Bohr magneton. n = 1, 2, 3, 4, 5 gives 1.73, 2.83, 3.87, 4.90, 5.92 BM.
Spin-only magnetic moments of the M2+ ions of the 3d serieswww.iitmedicoguide.comSpin-only magnetic moment of M²⁺ ions (high spin, free ions)0123456μ (BM)2.833.874.905.924.903.872.831.730Ti²⁺V²⁺Cr²⁺Mn²⁺Fe²⁺Co²⁺Ni²⁺Cu²⁺Zn²⁺d²d³d⁴d⁵d⁶d⁷d⁸d⁹d¹⁰unpaired:234543210www.iitmedicoguide.com
Unpaired electrons rise to five at d⁵ and then fall as electrons start pairing, so Mn²⁺ has the highest spin-only moment and Zn²⁺ (d¹⁰) is diamagnetic. Values are calculated from μ = √(n(n + 2)).
Worked example: Calculate the spin-only magnetic moment of Fe2+ (Z = 26). Which 3d M2+ ion would have μ = 3.87 BM?
Solution: Fe2+ is 3d6; in a free ion Hund's rule gives four unpaired electrons, so μ = √(4 × 6) = √24 = 4.90 BM. For μ = 3.87 BM, n(n + 2) = 15, so n = 3: a d3 ion (V2+) or a d7 ion (Co2+).

Coloured ions

In a transition metal ion with a partly filled d subshell, an electron can jump from a lower d orbital to a higher one (a d-d transition) by absorbing a particular wavelength of visible light. The colour seen is the complementary colour of the light absorbed. The ligands decide the size of the gap, so the same ion can have different colours in different complexes. Ions with d0 (Sc3+, Ti4+) or d10 (Zn2+, Cu+) configurations are colourless.

Ion (aqueous)Ti3+V3+Cr3+Mn2+Fe2+Fe3+Co2+Ni2+Cu2+
ColourPurpleGreenVioletPinkGreenYellowPinkGreenBlue

Complexes, catalysis, interstitial compounds and alloys

  • Complex formation: small ions with high charge and vacant d orbitals of suitable energy bind ligands easily, e.g. [Fe(CN)6]3−, [Cu(NH3)4]2+, [Ni(CN)4]2−.
  • Catalytic activity: comes from variable oxidation states and the ability to form complexes and to adsorb reactants on the surface. Examples: V2O5 in the contact process, finely divided iron in the Haber process, nickel in hydrogenation. Fe3+ catalyses the reaction between iodide and persulphate: 2Fe3+ + 2I− → 2Fe2+ + I2, then 2Fe2+ + S2O82− → 2Fe3+ + 2SO42−.
  • Interstitial compounds: small atoms such as H, C or N get trapped in the gaps of the metal lattice, e.g. TiC, Mn4N, Fe3H, VH0.56. They are usually non-stoichiometric, have higher melting points than the pure metals, are very hard, keep metallic conductivity and are chemically inert.
  • Alloys: transition metals have similar atomic radii, so one can replace another in the lattice. Examples: brass (Cu and Zn), bronze (Cu and Sn), and the many ferrous alloys used in steel.

Potassium dichromate, K2Cr2O7

Both of the following compounds are listed in the JEE Main and NEET syllabi, so learn their preparation and oxidising reactions.

4FeCr2O4 + 8Na2CO3 + 7O2 → 8Na2CrO4 + 2Fe2O3 + 8CO22Na2CrO4 + 2H+ → Na2Cr2O7 + 2Na+ + H2ONa2Cr2O7 + 2KCl → K2Cr2O7 + 2NaClChromite ore is fused with sodium carbonate in free access of air; the yellow chromate is acidified to orange dichromate, which is converted to the less soluble potassium salt.

Chromate and dichromate change into each other with pH: 2CrO42− (yellow) + 2H+ → Cr2O72− (orange) + H2O, and Cr2O72− + 2OH− → 2CrO42− + H2O. The chromate ion is tetrahedral; the dichromate ion is two tetrahedra sharing one corner, with a Cr-O-Cr angle of 126°. Chromium is +6 in both.

In acid, dichromate is a strong oxidising agent: Cr2O72− + 14H+ + 6e− → 2Cr3+ + 7H2O (E° = 1.33 V). It oxidises I− to I2, Fe2+ to Fe3+, Sn2+ to Sn4+ and H2S to S. Being available pure, K2Cr2O7 is used as a primary standard in volumetric analysis.

Potassium permanganate, KMnO4

2MnO2 + 4KOH + O2 → 2K2MnO4 + 2H2O3MnO42− + 4H+ → 2MnO4− + MnO2 + 2H2OPyrolusite (MnO2) is fused with KOH and an oxidising agent such as KNO3 to give dark green manganate, which disproportionates in neutral or acidic solution to purple permanganate. Commercially, manganate is oxidised electrolytically in alkaline solution.

Both ions are tetrahedral. The green manganate ion (Mn +6, d1) is paramagnetic; the purple permanganate ion (Mn +7, d0) is diamagnetic, its colour arising from charge transfer rather than a d-d transition.

  • Acidic medium: MnO4− + 8H+ + 5e− → Mn2+ + 4H2O (E° = 1.52 V). Oxidises I− to I2, Fe2+ to Fe3+, oxalate to CO2, H2S to S, sulphite to sulphate and nitrite to nitrate. The acid used is dilute H2SO4; HCl is avoided because permanganate oxidises it to Cl2.
  • Neutral or faintly alkaline medium: MnO4− + 2H2O + 3e− → MnO2 + 4OH−. Oxidises I− to iodate (IO3−), thiosulphate to sulphate and Mn2+ to MnO2.

The lanthanoids

  • Configuration: the 4f subshell fills from Ce to Lu; general configuration [Xe]4f1−145d0−16s2.
  • Oxidation state: +3 is characteristic. Ce4+ (4f0) exists and is a good oxidising agent (E°(Ce4+/Ce3+) = +1.74 V); Eu2+ (4f7) and Yb2+ (4f14) act as reducing agents; Tb4+ (4f7) is an oxidant.
  • Lanthanoid contraction: atomic and ionic (M3+) radii decrease steadily from La to Lu, because the added 4f electrons shield each other poorly from the growing nuclear charge. Consequences: 4d and 5d elements of the same group have nearly equal radii (Zr/Hf, Nb/Ta), so they are very hard to separate; the basic strength of the hydroxides decreases from La(OH)3 to Lu(OH)3.
  • Chemistry: early members are about as reactive as calcium. They burn in O2 to give Ln2O3, liberate H2 from dilute acids, and form carbides and nitrides on heating with C and N2.
  • Uses: mischmetall (about 95% lanthanoid metal and 5% iron, with traces of S, C, Ca and Al) is used in a magnesium-based alloy for bullets, shells and lighter flints. Mixed lanthanoid oxides are used as catalysts in petroleum cracking.

The actinoids

  • All actinoids are radioactive; the later members have very short half-lives and have been made only in nanogram quantities.
  • They show a wider range of oxidation states than lanthanoids (up to +7 for Np and Pu), because the 5f, 6d and 7s levels are close in energy. +3 is common, but for the early members higher states such as +4, +5 and +6 are important (e.g. U shows +6).
  • Actinoid contraction from element to element is greater than the lanthanoid contraction, because 5f electrons shield even more poorly than 4f electrons.
Common mistakes: (1) Removing 3d electrons before 4s when writing ion configurations. (2) Calling Zn a transition element; it is d-block but not transition. (3) Taking the colour of MnO4− as a d-d transition; Mn(VII) is d0. (4) Forgetting that in acid KMnO4 gains 5 electrons but K2Cr2O7 gains 6 per formula unit. (5) Explaining the similar size of Zr and Hf by anything other than the lanthanoid contraction.

JEE and NEET focus

  • Electronic configurations of 3d atoms and ions, including Cr and Cu, and the definition of a transition element.
  • Trends in oxidation states, E° values and stability, with reasons based on d0, d5, d10 and t2g3 configurations.
  • Spin-only magnetic moment calculations and the reason for colour; which ions are colourless.
  • Preparation of K2Cr2O7 and KMnO4, chromate-dichromate equilibrium, structures, and balanced oxidising reactions in acidic and neutral media.
  • Lanthanoid contraction, its causes and consequences; oxidation states of Ce, Eu and Yb; actinoids compared with lanthanoids.

Practice questions

Which of the following aqueous ions is colourless?

  1. Ti3+
  2. V3+
  3. Sc3+
  4. Cu2+
Show answer
C. Sc3+ is 3d0, so no d-d transition is possible.

The spin-only magnetic moment of Mn2+ (Z of Mn = 25) is:

  1. 3.87 BM
  2. 4.90 BM
  3. 5.92 BM
  4. 1.73 BM
Show answer
C. 3d5, five unpaired electrons: √35 = 5.92 BM.

Zirconium and hafnium have almost identical atomic radii because of:

  1. Inert pair effect
  2. Lanthanoid contraction
  3. Actinoid contraction
  4. Diagonal relationship
Show answer
B. Filling of 4f before the 5d series cancels the expected increase in size.

In acidic medium, the number of electrons gained by one MnO4− ion is:

  1. 1
  2. 3
  3. 5
  4. 6
Show answer
C. Mn goes from +7 to +2.

The element of the 3d series that shows the largest number of oxidation states is:

  1. Cr
  2. Fe
  3. Mn
  4. Cu
Show answer
C. Mn shows +2 to +7.

On adding NaOH to an orange solution of K2Cr2O7, the solution turns yellow because:

  1. Cr3+ is formed
  2. CrO42− is formed
  3. Cr is reduced to +3
  4. CrO5 is formed
Show answer
B. Cr2O72− + 2OH− → 2CrO42− + H2O; Cr stays +6.

Which 3d metal has a positive E°(M2+/M)?

  1. Zn
  2. Ni
  3. Fe
  4. Cu
Show answer
D. E°(Cu2+/Cu) = +0.34 V, so copper does not displace H2 from dilute acids.

Actinoids show a larger number of oxidation states than lanthanoids because:

  1. They are radioactive
  2. 5f, 6d and 7s orbitals have comparable energies
  3. They have larger atomic radii
  4. They have more electrons in the s subshell
Show answer
B. Electrons from all three levels can take part in bonding.
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