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Physics · Class 12 · Chapter 2

Electrostatic Potential and Capacitance

Potential lets you handle electrostatics with scalars instead of vectors, and capacitors are where that idea turns into circuit problems. Expect questions on combinations, dielectrics and energy in every paper.

In this chapter: electrostatic potential and potential difference, potential of a point charge, a dipole and a system of charges, equipotential surfaces and E = −dV/dr, potential energy of charges and of a dipole in a field, conductors in electrostatics, dielectrics and polarisation, capacitance, the parallel plate capacitor, dielectric slabs, series and parallel combinations, energy stored.

Potential and potential difference

The electrostatic force is conservative, so the work done in moving a charge between two points does not depend on the path. This lets us define potential energy, and from it potential. The potential at a point is the work done by an external agent in bringing a unit positive charge from infinity to that point without acceleration:

V = W∞→Pqunit volt (V) = J C−1; only differences of potential are physically meaningful, and we choose V = 0 at infinity

Point charge, dipole, system of charges

Point charge: V = q4πε0rShort dipole: V = p cos θ4πε0r2System: V = k(q1/r1 + q2/r2 + …)

The dipole potential is zero everywhere on the equatorial plane (θ = 90°) and falls as 1/r2. Potential is a scalar, so for a system of charges you add values with their signs; there is no direction to worry about, which is why it is usually easier to find V first and then E.

For a uniformly charged spherical shell of radius R, V = kq/r outside and V = kq/R everywhere inside. The field inside is zero, but the potential inside is not zero; it is constant.

Equipotential surfaces

An equipotential surface has the same potential at every point. No work is done in moving a charge along it, and so the field is always normal to the equipotential surface. For a point charge these surfaces are concentric spheres; in a uniform field they are planes perpendicular to the field.

E = −dVdrE points in the direction in which V decreases fastest

Where equipotentials are closely spaced, the field is strong. In a uniform field, E = V/d between two surfaces a distance d apart.

Equipotential surfaces for a point charge and a uniform fieldwww.iitmedicoguide.com+V₁V₂V₃(a) Point charge +qequal steps of V: spacing grows outwardV₁V₂V₃E(b) Uniform fieldV₁ > V₂ > V₃ (E points to lower V)equipotentials: planes normal to Efield lineequipotential surfacewww.iitmedicoguide.com
Field lines cut equipotential surfaces at right angles. For a point charge, surfaces drawn at equal steps of potential get farther apart as you move out, because the field weakens.

Potential energy

The potential energy of a system of point charges is the work needed to assemble them from infinity. For two charges:

U = q1q24πε0r12for three charges, add the three pair terms: U = k(q1q2/r12 + q2q3/r23 + q1q3/r13)

Keep the signs of the charges: U is positive for like charges (work must be done to push them together) and negative for unlike charges. In an external field, a single charge q at a point of potential V has energy qV. Energies in atomic physics are often in electron volts: 1 eV = 1.6 × 10−19 J.

Dipole in a uniform field

U(θ) = −pE cos θ = −p · EWork to rotate from θ1 to θ2: W = pE(cos θ1 − cos θ2)

U is minimum (−pE) at θ = 0, which is stable equilibrium, and maximum (+pE) at θ = 180°, which is unstable. Rotating the dipole from 0 to 180° needs work 2pE.

Conductors in electrostatics

  • The field inside a conductor is zero, because free electrons move until the internal field is cancelled.
  • Just outside the surface, the field is normal to the surface and equals σ/ε0.
  • There is no net charge in the interior; any excess charge sits on the surface.
  • The whole conductor, inside and surface, is at one potential.
  • Inside a cavity with no charge in it, the field is zero, whatever charges or fields are outside. This is electrostatic shielding, the reason a car or a metal cage is a safe place during lightning.

Dielectrics and polarisation

A dielectric has no free charges. In an external field its molecules either develop an induced dipole moment (non-polar molecules) or their permanent dipoles partly line up (polar molecules). The dielectric gets a net dipole moment per unit volume, the polarisation P = χeε0E, where χe is the electric susceptibility. The result is equivalent to bound charge densities ±σp on the faces, which set up a field opposite to the applied field and reduce it. The dielectric constant is K = 1 + χe = ε/ε0.

Capacitors

A capacitor is two conductors carrying charges +Q and −Q. The potential difference V between them is proportional to Q, and the ratio is the capacitance:

C = QVunit farad (F) = C V−1; practical values are μF, nF and pF

C depends only on the geometry and the medium between the conductors, not on Q or V. If the voltage across a capacitor exceeds a limit, the medium ionises and the capacitor leaks; for air this dielectric strength is about 3 × 106 V m−1.

Parallel plate capacitor

For plates of area A separated by d (with d small compared with the plate size), the field between them is E = σ/ε0 = Q/(ε0A) and the voltage is Ed. So

C0 = ε0Adwith a dielectric filling the gap: C = Kε0Ad = KC0slab of thickness t (t < d): C = ε0Ad − t + t/K

A metal slab of thickness t acts like K → ∞, giving C = ε0A/(d − t).

Dielectric (K) insertedBattery disconnected (Q fixed)Battery connected (V fixed)
CapacitanceKC0KC0
ChargeQ0 (same)KQ0
VoltageV0/KV0 (same)
Field between platesE0/KE0 (same)
Energy storedU0/KKU0

Combination of capacitors

Series: 1/C = 1/C1 + 1/C2 + 1/C3 + …Parallel: C = C1 + C2 + C3 + …

In series each capacitor carries the same charge and the voltages add; the equivalent is smaller than the smallest. In parallel each has the same voltage and the charges add. Notice that these are the reverse of the rules for resistors.

Capacitors in series and in parallelwww.iitmedicoguide.com(a) SeriesC₁C₂C₃ABsame charge Q on eachV = V₁ + V₂ + V₃1/C = 1/C₁ + 1/C₂ + 1/C₃(b) ParallelC₁C₂C₃ABsame V across eachQ = Q₁ + Q₂ + Q₃C = C₁ + C₂ + C₃www.iitmedicoguide.com
Capacitors in series share the same charge, while capacitors in parallel share the same potential difference.

Energy stored in a capacitor

Charging a capacitor means moving small charges dq against the growing voltage q/C. Adding up the work gives

U = Q22C = ½CV2 = ½QVEnergy density: u = ½ε0E2

The energy is stored in the electric field between the plates. Use Q2/2C when the charge is fixed and ½CV2 when the voltage is fixed; that choice alone settles most "what happens to the energy" questions.

Worked example: Capacitors of 2 μF, 3 μF and 6 μF are connected in series across a 12 V battery. Find the equivalent capacitance, the charge, the voltage across each and the total energy.
Solution: 1/C = 1/2 + 1/3 + 1/6 = 1, so C = 1 μF. Charge on each: Q = CV = 1 × 12 = 12 μC. Voltages: 12/2 = 6 V, 12/3 = 4 V and 12/6 = 2 V, which add to 12 V as they should. Energy: U = ½ × 1 × 10−6 × 122 = 72 μJ.
Worked example: A parallel plate capacitor has plates of area 6 × 10−3 m2 separated by 3 mm of air. Find its capacitance and the charge on each plate when connected to 100 V.
Solution: C = ε0A/d = (8.85 × 10−12 × 6 × 10−3)/(3 × 10−3) = 1.77 × 10−11 F = 17.7 pF. Charge Q = CV = 1.77 × 10−9 C.
Common mistakes: (1) Saying the potential inside a charged shell or conductor is zero because the field is zero; it is constant and equal to the surface value. (2) Dropping the sign of the charges in V or U. (3) Using the resistor rules for capacitors. (4) Forgetting whether the battery is connected when a dielectric is inserted or plates are pulled apart. (5) Writing the dipole energy as +pE cos θ; the minus sign is what makes θ = 0 stable.

JEE and NEET focus

  • Potential and potential energy of a system of point charges, with signs.
  • E = −dV/dr, including finding E from a given V(x) and the idea of equipotential surfaces.
  • Work done in rotating a dipole in a uniform field.
  • Parallel plate capacitor with dielectric or metal slabs, and the battery connected or disconnected cases.
  • Series and parallel networks, charge sharing between two capacitors and energy stored.

Practice questions

Charges +q, +q, −q and −q are placed at the corners of a square. The potential at the centre is:

  1. 4kq/r
  2. 2kq/r
  3. zero
  4. kq/r
Show answer
C. All four are at the same distance r and the charges add to zero.

The work done in moving a 2 μC charge through 5 cm along an equipotential surface of 100 V is:

  1. 200 μJ
  2. 10 μJ
  3. zero
  4. 100 μJ
Show answer
C. W = qΔV and ΔV = 0 along an equipotential.

The potential in a region is V = 5x2 volt (x in metre). The electric field at x = 2 m is:

  1. 20 V m−1 along +x
  2. 20 V m−1 along −x
  3. 10 V m−1 along −x
  4. 40 V m−1 along −x
Show answer
B. E = −dV/dx = −10x = −20 V m−1.

A charged capacitor is disconnected from the battery and a dielectric of constant K is inserted to fill the gap. The stored energy:

  1. becomes K times
  2. becomes 1/K times
  3. stays the same
  4. becomes K2 times
Show answer
B. Q is fixed and C becomes KC, so U = Q2/2C falls by K.

Using three 3 μF capacitors, the maximum and minimum capacitances possible are:

  1. 9 μF and 1 μF
  2. 9 μF and 3 μF
  3. 6 μF and 1 μF
  4. 3 μF and 1 μF
Show answer
A. All in parallel give 9 μF; all in series give 3/3 = 1 μF.

The energy stored in a 10 μF capacitor charged to 200 V is:

  1. 2 J
  2. 0.4 J
  3. 0.2 J
  4. 0.02 J
Show answer
C. ½ × 10−5 × (200)2 = 0.2 J.

A metal slab of thickness d/2 is placed between the plates of an air capacitor of capacitance C0 and separation d. The new capacitance is:

  1. C0/2
  2. C0
  3. 2C0
  4. infinite
Show answer
C. C = ε0A/(d − d/2) = 2ε0A/d.

An electric dipole in a uniform field is in stable equilibrium when the angle between p and E is:

  1. 0°
  2. 90°
  3. 180°
  4. 45°
Show answer
A. U = −pE cos θ is minimum at θ = 0.
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