Latest
  • Admissions openClass 11 Science, 2027‑28: JEE, NEET and MHT‑CET with junior college and hostel under one roofApply now
  • IMGSAT 2027Free scholarship and admission test for Class 10 students, every Saturday and Sunday at our Nashik campusRegister
  • Free Foundation 2026‑27Evening classes for Class 10 in Physics, Chemistry, Maths and Biology, taught by our IITian and doctor facultyJoin free

+91 70303 00666

Physics · Class 12 · Chapter 5

Magnetism and Matter

A bar magnet behaves like a current loop, and materials respond to a magnetic field in three distinct ways. The chapter is short, and most questions test definitions, the signs and sizes of susceptibility, and the effect of temperature.

In this chapter: field lines of a bar magnet, the bar magnet as an equivalent solenoid, a magnetic dipole in a uniform field, the electrostatic analogy, Gauss's law for magnetism, magnetisation, magnetic intensity H, susceptibility and permeability, diamagnetism, paramagnetism, ferromagnetism, Curie temperature and hysteresis.

The bar magnet

A freely suspended bar magnet settles roughly along the geographic north-south line. Its two poles cannot be isolated: cut a magnet in two and each piece is a complete magnet with its own north and south pole. Magnetic field lines of a bar magnet have these properties:

  • They form continuous closed loops: outside the magnet they run from N to S, and inside from S to N. Electric field lines of a dipole, by contrast, begin on +q and end on −q.
  • The tangent at any point gives the direction of B, and the density of lines shows its magnitude.
  • Two field lines never cross.
Magnetic field lines of a bar magnetwww.iitmedicoguide.comSNoutside: N to S; inside the magnet (dashed): S to N, so every line is a closed loopwww.iitmedicoguide.com
The field of a bar magnet looks like that of an electric dipole outside the magnet. Inside, the lines continue from S to N, so magnetic field lines have no starting or ending point.

Bar magnet as an equivalent solenoid

The field of a bar magnet and that of a current-carrying solenoid of the same size look almost identical, and the axial field of a finite solenoid at large distance has exactly the form of a dipole field. So a bar magnet can be treated as a solenoid with magnetic moment m = NIA, directed from S to N inside the magnet. For a short magnet (or any magnetic dipole) at distance r:

Axial: B = μ04π · 2mr3Equatorial: B = −μ04π · mr3  (opposite to m)

Dipole in a uniform magnetic field

τ = m × B,   τ = mB sin θU = −m · B = −mB cos θSmall oscillations: T = 2π√I/mBI is the moment of inertia of the magnet about the axis of rotation; unit of m is A m2 (or J T−1)

The energy is minimum (−mB) when m is along B, which is stable equilibrium, and maximum (+mB) when it is opposite, which is unstable. This is how a compass needle aligns itself.

Worked example: A short bar magnet of moment 0.32 J T−1 is placed in a uniform field of 0.15 T. Find the torque when its axis is at 30° to the field, and its potential energy in the stable and unstable positions.
Solution: τ = mB sin 30° = 0.32 × 0.15 × 0.5 = 0.024 N m. Stable (θ = 0°): U = −mB = −0.048 J. Unstable (θ = 180°): U = +0.048 J.

The electrostatic analogy

Results for the magnetic dipole can be read off from those for the electric dipole by the replacements below.

QuantityElectrostaticsMagnetism
Constant1/ε0μ0
Dipole momentpm
Axial field (short dipole)2p/(4πε0r3)μ02m/(4πr3)
Torque in uniform fieldp × Em × B
Potential energy−p · E−m · B

Magnetism and Gauss's law

∮ B · dS = 0

The net magnetic flux through any closed surface is zero, because every field line that enters a closed surface also leaves it. In electrostatics the flux equals q/ε0; the magnetic version is zero because isolated magnetic poles (monopoles) are not known to exist. The simplest magnetic element is a dipole or a current loop.

Magnetisation and magnetic intensity

Electrons in atoms have magnetic moments from their orbital motion and their spin. In a material, these add up to a net moment per unit volume, the magnetisation:

M = mnetVunit A m−1, same as H

Place a material inside a solenoid with n turns per unit length carrying current I. The field due to the current alone is B0 = μ0nI. We define the magnetic intensity H = B0/μ0, so H = nI depends only on the external current. The total field is

B = μ0(H + M)M = χH,   B = μ0(1 + χ)H = μ0μrH = μHμr = 1 + χ

χ is the magnetic susceptibility, a dimensionless number that measures how a material responds to a field. μr is the relative permeability and μ = μ0μr the permeability.

Worked example: A solenoid with 1000 turns per metre carries 2 A and has a core of relative permeability 400. Find H, B and M in the core.
Solution: H = nI = 1000 × 2 = 2 × 103 A m−1. B = μrμ0H = 400 × 4π × 10−7 × 2 × 103 ≈ 1.0 T. M = (μr − 1)H = 399 × 2 × 103 ≈ 8 × 105 A m−1. Notice that M is far larger than H; almost all of B comes from the core.

Magnetic properties of materials

 DiamagneticParamagneticFerromagnetic
χsmall, negative (−1 ≤ χ < 0)small, positive (0 < χ < ε)very large, positive (χ ≫ 1)
μrslightly less than 1slightly more than 1much more than 1
In a non-uniform fieldmoves from stronger to weaker field (repelled)moves weakly from weaker to stronger fieldstrongly attracted
Examplesbismuth, copper, lead, silicon, nitrogen (STP), water, sodium chloridealuminium, sodium, calcium, oxygen (STP), copper chlorideiron, cobalt, nickel, gadolinium

(In the table, ε stands for a small positive number.)

Diamagnetism

Atoms of a diamagnetic substance have no net magnetic moment. An external field changes the orbital motion of the electrons so that a small moment is induced opposite to the field (a Lenz's law effect). Field lines are pushed out of the material. Diamagnetism is present in all substances but is usually masked by the other effects. A superconductor cooled below its critical temperature is a perfect diamagnet: χ = −1, μr = 0, and field lines are completely expelled. This is the Meissner effect.

Paramagnetism

Each atom has a permanent magnetic moment, but thermal motion keeps the moments randomly oriented. An external field aligns them partly, giving a small magnetisation along the field. Lower temperature and stronger field increase the alignment. Curie's law:

χ = C μ0T   (M ∝ B0/T)C is the Curie constant of the material; T in kelvin

Ferromagnetism

In a ferromagnet the atomic moments of neighbouring atoms line up spontaneously over small regions called domains, each about 1 mm in size and containing around 1011 atoms. Without a field the domains point in random directions and cancel. An applied field makes favourably oriented domains grow and others rotate, so the material becomes strongly magnetised.

Above the Curie temperature Tc, a ferromagnet becomes paramagnetic, with χ = C/(T − Tc) for T > Tc. NCERT lists Tc as 1043 K for iron, 1394 K for cobalt, 631 K for nickel and 317 K for gadolinium. Materials whose magnetisation persists after the field is removed are called hard ferromagnets (alnico, used for permanent magnets); those that lose it easily are soft ferromagnets (soft iron).

Hysteresis

Hysteresis, and the choice of materials for permanent magnets and electromagnets, belonged to a section that the rationalised NCERT book dropped. They are kept here because older papers and some state exams still use them, so check your current syllabus before spending long on this part.

If H is increased from zero, B rises along the initial curve to saturation. When H is brought back to zero, B does not return to zero; the value left over is the retentivity (remanence). A reverse field, the coercivity, is needed to make B zero. Taking H through a full cycle traces the hysteresis loop, and the area enclosed is the energy dissipated per unit volume per cycle.

Magnetic hysteresis loop of a ferromagnetwww.iitmedicoguide.comHBabcdefsaturationOb = retentivityOc = coercivityinitial curve Oa (dashed) area of loop = energy lost per cycle per unit volumewww.iitmedicoguide.com
The hysteresis loop of a ferromagnet. Ob is the retentivity and Oc the coercivity; B lags behind H throughout the cycle.
  • Permanent magnets need high retentivity and high coercivity, which means a broad loop (steel, alnico, cobalt steel, ticonal).
  • Electromagnet cores need high permeability and low retentivity, so that the magnetism disappears when the current is switched off (soft iron).
  • Transformer cores are taken through many cycles, so they need a narrow loop (low hysteresis loss), high permeability and high resistivity.
Common mistakes: (1) Saying field lines of a magnet go from N to S inside it; inside they go from S to N. (2) Mixing up the signs: diamagnetic χ is negative, paramagnetic χ is small and positive. (3) Using Curie's law χ ∝ 1/T for a ferromagnet below Tc. (4) Choosing soft iron for a permanent magnet; soft iron has low retentivity and coercivity. (5) Forgetting that H depends only on the free current, while B includes the material's contribution.

JEE and NEET focus

  • Torque, potential energy and work done in rotating a magnetic dipole.
  • Relations among B, H, M, χ and μr, with numericals on a solenoid with a core.
  • Properties and examples of dia-, para- and ferromagnetic substances.
  • Curie's law and the Curie temperature.
  • Reading retentivity and coercivity from a hysteresis loop and choosing materials for magnets and cores (outside the rationalised NCERT book, but still seen in older papers).

Practice questions

The net magnetic flux through any closed surface is:

  1. μ0 times the enclosed current
  2. zero
  3. equal to the pole strength
  4. infinite
Show answer
B. Gauss's law for magnetism; there are no isolated poles.

The susceptibility of a diamagnetic substance is:

  1. small and positive
  2. large and positive
  3. small and negative
  4. zero
Show answer
C. The induced moment opposes the applied field.

A paramagnetic salt has χ = 1.2 × 10−5 at 300 K. At 200 K its susceptibility will be:

  1. 0.8 × 10−5
  2. 1.2 × 10−5
  3. 1.8 × 10−5
  4. 2.7 × 10−5
Show answer
C. χ ∝ 1/T, so χ = 1.2 × 10−5 × 300/200.

Above its Curie temperature, a ferromagnetic material becomes:

  1. diamagnetic
  2. paramagnetic
  3. a superconductor
  4. more strongly ferromagnetic
Show answer
B. Thermal agitation destroys the domain alignment.

A material suitable for making permanent magnets should have:

  1. low retentivity, low coercivity
  2. high retentivity, low coercivity
  3. high retentivity, high coercivity
  4. low retentivity, high coercivity
Show answer
C. It must keep its magnetism and resist demagnetisation.

For a superconductor below its critical temperature, the susceptibility is:

  1. +1
  2. 0
  3. −1
  4. very large
Show answer
C. It is a perfect diamagnet (μr = 0).

A magnet of moment 2 A m2 is held at 30° to a uniform field of 0.5 T. The torque on it is:

  1. 1.0 N m
  2. 0.87 N m
  3. 0.5 N m
  4. 0.25 N m
Show answer
C. τ = mB sin 30° = 2 × 0.5 × 0.5 = 0.5 N m.

A material has susceptibility 599. Its relative permeability is:

  1. 598
  2. 599
  3. 600
  4. 1/599
Show answer
C. μr = 1 + χ.
Call WhatsApp Apply
Chat with us on WhatsApp